Compute 3\(\begin{pmatrix}1&-2\\0&4\end{pmatrix}\).

Compute -2\(\begin{pmatrix}5&0&-1\end{pmatrix}\).

For \(A=\begin{pmatrix}2&-3\\1&0\end{pmatrix}\), compute 0A.

Compute (1/2)\(\begin{pmatrix}6&-4\\10&8\end{pmatrix}\).

Find x if 4\(\begin{pmatrix}x&2\\1&-1\end{pmatrix}\) has top-left entry 12.

For \(A=\begin{pmatrix}1&2\\3&4\end{pmatrix}\), compute 2A + 3A.

For \(A=\begin{pmatrix}2&-1\\0&3\end{pmatrix}\) and \(B=\begin{pmatrix}1&4\\-2&5\end{pmatrix}\), compute 2A - B.

Find A if 3A = \(\begin{pmatrix}6&-9\\0&12\end{pmatrix}\).

Verify that 2(A + B) = 2A + 2B for \(A=\begin{pmatrix}1&0\\2&-1\end{pmatrix}\) and \(B=\begin{pmatrix}3&4\\-2&5\end{pmatrix}\).

A student says -A means take the reciprocal of every entry of A. Diagnose this using \(A=\begin{pmatrix}2&-1\\0&4\end{pmatrix}\).