What condition lets a charged particle pass undeflected through crossed electric and magnetic fields?

State the selected speed in a velocity selector.

A velocity selector has \(E=2.4\times10^4\,\mathrm{N\,C^{-1}}\) and \(B=0.12\,\mathrm{T}\). Find the selected speed.

Does the selected speed \(v=E/B\) depend on the particle charge magnitude?

A selector uses \(B=0.25\,\mathrm{T}\) to pass particles at \(3.0\times10^5\,\mathrm{m\,s^{-1}}\). Find the required electric field.

After speed selection, a singly charged ion moves in radius \(0.30\,\mathrm{m}\) in \(0.50\,\mathrm{T}\) at \(2.0\times10^5\,\mathrm{m\,s^{-1}}\). Find its mass.

State the momentum relation for a charged particle moving perpendicular to a magnetic field in a circular path.

Why can a velocity selector pass both positive and negative particles of the same speed if their paths are arranged correctly?

A particle with selected speed \(1.5\times10^5\,\mathrm{m\,s^{-1}}\) enters a magnetic analyzer with \(B=0.40\,\mathrm{T}\) and radius \(0.10\,\mathrm{m}\). Find \(m/|q|\).

In a magnetic analyzer, which particle has the larger radius: larger \(m/|q|\) or smaller \(m/|q|\), at the same speed and field?

What happens in a velocity selector if a particle is slower than \(E/B\), assuming electric and magnetic forces oppose?

What happens in a velocity selector if a particle is faster than \(E/B\), assuming electric and magnetic forces oppose?

Derive \(v=E/B\) for a velocity selector.

Derive \(m/|q|=rB/v\) for a magnetic analyzer.

A mass spectrometer selects speed \(2.0\times10^5\,\mathrm{m\,s^{-1}}\). Two singly charged ions have radii \(0.20\,\mathrm{m}\) and \(0.25\,\mathrm{m}\) in the same magnetic field. Compare their masses.

A particle has \(q=3.2\times10^{-19}\,\mathrm{C}\), speed \(4.0\times10^5\,\mathrm{m\,s^{-1}}\), and radius \(0.50\,\mathrm{m}\) in \(0.20\,\mathrm{T}\). Find its mass.

Why is a velocity selector often placed before a magnetic analyzer?

A particle passes undeflected through crossed fields, then enters an analyzer. If \(E\) in the selector is doubled while selector \(B\) is unchanged, how does analyzer radius change?

A selector has electric force upward and magnetic force downward on positive particles at the selected speed. What happens to negative particles moving with the same velocity?

Explain how a velocity selector and magnetic analyzer together can identify ions by mass-to-charge ratio.