AcademyGroups

Academy

Subgroups

Level 1 - Math I (Physics) topic page in Groups.

Principle

A subgroup is a subset of a group that is itself a group using the same operation. The operation is not reinvented; it is inherited from the parent group.

Subgroups let a large symmetry system be studied through smaller collections of transformations, such as only the rotations inside a full polygon symmetry group.

Notation

  • \((G,*)\) is the parent group.
  • \(H\) is a subset of \(G\).
  • \(H\subseteq G\) means every element of \(H\) is also an element of \(G\).
  • \(e\) is the identity element of the parent group.
  • \(h\) is an element of \(H\).
  • \(h^{-1}\) is the inverse of \(h\) in the parent group.
  • \(H\le G\) means \(H\) is a subgroup of \(G\).
Subgroup notation
\[H\le G\]

Method

To test whether \(H\) is a subgroup of \(G\):

  1. Check that \(H\) is not empty.
  2. Check that if \(h_1,h_2\in H\), then \(h_1*h_2\in H\).
  3. Check that if \(h\in H\), then \(h^{-1}\in H\).
  4. Use the same operation \(*\) as the parent group.

Associativity does not need a separate proof once \(H\) uses the operation from \(G\), because associativity is inherited from the parent group.

Rules

  • Every subgroup contains the identity element of the parent group.
  • A subgroup uses the same operation as the parent group.
  • Closure under products keeps the subset stable under the operation.
  • Closure under inverses makes every allowed operation reversible inside the subset.
  • A subset that omits required inverses is not a subgroup.

Examples

Let \(2\mathbb Z\) be the set of even integers. Test it as a subgroup of \((\mathbb Z,+)\).

The set is non-empty because \(0\in2\mathbb Z\).

For closure under addition, write two even integers as \(2m\) and \(2n\), where \(m,n\in\mathbb Z\). Then:

Even integer closure
\[2m+2n=2(m+n)\in2\mathbb Z\]

For inverses under addition, the inverse of \(2m\) is \(-(2m)\). Since \(-m\) is also an integer:

Even integer inverse
\[-(2m)=2(-m)\in2\mathbb Z\]

The identity is \(0\), and \(0=2\cdot0\), so \(0\in2\mathbb Z\). Therefore \(2\mathbb Z\le\mathbb Z\) under addition.

Checks

  • Use the same operation as the parent group.
  • Check that inverses stay inside the subset.
  • Check that the identity is the parent identity, not a new element.
  • Do not assume every subset of a group is a subgroup.