AcademyTemperature and Heat

Academy

Heat as Energy Transfer

Level 1 - Physics topic page in Temperature and Heat.

Principle

Heat is energy transferred because of a temperature difference.

An object does not contain heat. It contains internal energy, and heat is one way that energy crosses the boundary of a system.

Notation

\(Q\)
energy transferred as heat
\(\mathrm{J}\)
\(m\)
mass
\(\mathrm{kg}\)
\(c\)
specific heat capacity
\(\mathrm{J\,kg^{-1}\,K^{-1}}\)
\(C\)
heat capacity of an object
\(\mathrm{J\,K^{-1}}\)
\(\Delta T\)
temperature change
\(\mathrm{K}\)
\(P\)
power supplied to the object
\(\mathrm{W}\)

Method

For a single material with no phase change, the temperature change is proportional to the energy added and inversely proportional to the heat capacity.

Object heat capacity
\[C=mc\]
This is the heat required per unit temperature change for the whole object.
Temperature-change energy
\[Q=C\Delta T\]
Specific heat form
\[Q=mc\Delta T\]
Sign convention
\[Q>0\Rightarrow \Delta T>0\quad\text{for }c>0\]

If power is supplied steadily and there is no heat loss, the same relation becomes a rate equation.

Power input
\[P=\frac{dQ}{dt}\]
Temperature rate
\[P=mc\frac{dT}{dt}\]
Heating rate
\[\frac{dT}{dt}=\frac{P}{mc}\]

The sign convention belongs to the chosen system. Heat added to the system is positive; heat removed from it is negative.

Rules

These are the compact relations for heat transfer that changes temperature without a phase change.

Heat capacity
\[C=mc\]
Temperature change
\[Q=mc\Delta T\]
Temperature interval
\[\Delta T=T_f-T_i\]
Heating rate
\[\frac{dT}{dt}=\frac{P}{mc}\]

Examples

Question
How much heat is required to warm
\[0.75\,\mathrm{kg}\]
of water from
\[18\,\mathrm{^\circ C}\]
to
\[42\,\mathrm{^\circ C}\]
? Use
\[c=4190\,\mathrm{J\,kg^{-1}\,K^{-1}}\]
Answer
\[\Delta T=42-18=24\,\mathrm{K}\]
\[Q=mc\Delta T=(0.75)(4190)(24)=7.5\times10^4\,\mathrm{J}\]

Checks

  • Heat is energy in transfer, not energy stored in an object.
  • Positive \(Q\) means energy enters the chosen system.
  • The formula \(Q=mc\\Delta T\) does not include phase changes.
  • A large heat capacity means the same heat input gives a smaller temperature change.