AcademyLinear Maps

Academy

Eigenvectors

Level 1 - Math I (Physics) topic page in Linear Maps.

Principle

An eigenvector is a non-zero vector whose direction is preserved by a linear map. The vector may be stretched, shrunk, reversed, or unchanged, but it stays on the same line.

Eigenvector equation
\[A\mathbf v=\lambda\mathbf v\]

In physics, eigenvectors often describe independent modes: principal axes, polarisation states, or directions that respond without mixing.

Notation

\(\mathbf v\)
non-zero eigenvector
\(\lambda\)
eigenvalue belonging to the eigenvector
\(A-\lambda I\)
matrix used to solve for eigenvectors
\(\mathbf 0\)
zero vector
\(c\mathbf v\)
non-zero scalar multiple of an eigenvector

If \(\\mathbf v\) is an eigenvector, every non-zero multiple of \(\\mathbf v\) is also an eigenvector with the same eigenvalue.

Method

Step 1: Start from a known eigenvalue

Eigenvectors are found after an eigenvalue has been identified.

Step 2: Solve a homogeneous system

Substitute \(\\lambda\) into \(A-\\lambda I\) and solve

Eigenvector system
\[(A-\lambda I)\mathbf v=\mathbf 0\]

Step 3: Exclude the zero vector

The zero vector always solves the homogeneous system, but it is not an eigenvector.

Rules

Scalar multiple rule
\[A(c\mathbf v)=cA\mathbf v=c\lambda\mathbf v=\lambda(c\mathbf v)\]
Non-zero condition
\[\mathbf v\ne\mathbf 0\]

Eigenvectors for distinct eigenvalues are linearly independent in standard finite-dimensional settings.

Examples

Question
Find an eigenvector for
\[A=\begin{pmatrix}2&0\\0&5\end{pmatrix}\]
with
\[\lambda=2\]
Answer
Solve
\[(A-2I)\mathbf v=\mathbf0\]
This gives
\[y=0\]
so one eigenvector is
\[(1,0)\]

Checks

  • Do not list the zero vector as an eigenvector.
  • Eigenvectors belong to a particular eigenvalue.
  • Any non-zero scalar multiple represents the same eigenvector direction.
  • Solve \((A-\\lambda I)\\mathbf v=\\mathbf0\), not \(A\\mathbf v=\\mathbf0\) unless \(\\lambda=0\).