AcademyComplex Equations

Academy

Complex Functions

Level 1 - Math I (Physics) topic page in Complex Equations.

Principle

A function of a complex variable takes a complex input and returns a complex output. The main functions needed here are the exponential, trigonometric, and hyperbolic functions.

Complex input
\[z=x+iy,\quad x,y\in\mathbb R\]

The complex exponential is the central example because it connects growth, rotation, and periodicity.

Notation

  • \(z=x+iy\) is a complex input.
  • \(x=\operatorname{Re}(z)\) is the real part.
  • \(y=\operatorname{Im}(z)\) is the imaginary part.
  • \(e^z\) is the complex exponential.
  • \(\sin z\), \(\cos z\), \(\sinh z\), and \(\cosh z\) are complex-valued functions.

Method

Write \(z=x+iy\) and split the exponential:

Split exponential
\[e^z=e^{x+iy}=e^xe^{iy}\]

Use Euler's formula for the imaginary exponential:

Euler substitution
\[e^{iy}=\cos y+i\sin y\]

Therefore:

Complex exponential form
\[e^z=e^x(\cos y+i\sin y)\]

This immediately gives:

Real part
\[\operatorname{Re}(e^z)=e^x\cos y\]
Imaginary part
\[\operatorname{Im}(e^z)=e^x\sin y\]
Modulus
\[|e^z|=e^x=e^{\operatorname{Re}(z)}\]
Argument
\[\arg(e^z)=y\quad\text{mod }2\pi\]

Rules

Define the trigonometric and hyperbolic functions using exponentials:

Cosine definition
\[\cos z=\frac{e^{iz}+e^{-iz}}{2}\]
Sine definition
\[\sin z=\frac{e^{iz}-e^{-iz}}{2i}\]
Hyperbolic cosine definition
\[\cosh z=\frac{e^z+e^{-z}}{2}\]
Hyperbolic sine definition
\[\sinh z=\frac{e^z-e^{-z}}{2}\]

Useful identities follow by substituting \(iz\):

Complex trig hyperbolic links
\[\cos(iz)=\cosh z,\quad \sin(iz)=i\sinh z\]
Complex hyperbolic trig links
\[\cosh(iz)=\cos z,\quad \sinh(iz)=i\sin z\]

Examples

Find the modulus of:

Example target
\[e^{(1+i)(2-i)}\]

First multiply the exponent:

Exponent product
\[(1+i)(2-i)=2-i+2i-i^2=3+i\]

So:

Example exponential
\[e^{(1+i)(2-i)}=e^{3+i}\]

The modulus of \(e^{x+iy}\) is \(e^x\), so:

Example modulus
\[|e^{3+i}|=e^3\]

Checks

  • The exponential \(e^z\) is periodic in the imaginary direction: \(e^{z+2\pi i}=e^z\).
  • The exponential never equals zero because \(|e^z|=e^{\operatorname{Re}(z)}\gt0\).
  • The argument of \(e^z\) is only determined modulo \(2\pi\).
  • Complex trigonometric and hyperbolic functions usually have complex values, even when their names are familiar from real calculus.