Academy
Linear Complex Equations
Level 1 - Math I (Physics) topic page in Complex Equations.
Principle
A linear complex equation is a first-degree equation for an unknown complex number. It has the same algebraic shape as a real linear equation, but the coefficients and the solution may be complex numbers.
Because every non-zero complex number has a reciprocal, a linear complex equation with \(a\ne0\) has exactly one complex solution.
Notation
- \(z\) is the unknown complex number.
- \(a\) is the coefficient of \(z\).
- \(b\) is the constant term.
- \(\overline{a}\) is the complex conjugate of \(a\).
- \(|a|\) is the modulus of \(a\).
Method
Start with the equation:
Subtract \(b\) from both sides:
Divide by \(a\), which is allowed because \(a\ne0\):
If the denominator is complex, write the quotient in standard form by multiplying top and bottom by the conjugate of the denominator:
The denominator \(|a|^2\) is real and positive, so the final expression can be separated into real and imaginary parts.
Rules
- A degree-one complex equation has one solution when the coefficient of \(z\) is not zero.
- If \(a=0\) and \(b\ne0\), the equation has no solution.
- If \(a=0\) and \(b=0\), every complex number is a solution.
- Complex numbers are not ordered, so solving does not involve choosing a larger or smaller solution.
Examples
Solve:
First isolate \(z\):
Divide by \(2-i\):
Multiply top and bottom by \(2+i\):
Compute the numerator and denominator:
Therefore:
Checks
- Check that the coefficient of \(z\) is not zero before dividing.
- Use the conjugate of the denominator, not the numerator, when simplifying a complex quotient.
- Substitute the result back into the original equation to catch sign errors.
- Keep the final answer in standard form \(x+iy\) unless polar form is requested.