Academy
Quadratic Complex Equations
Level 1 - Math I (Physics) topic page in Complex Equations.
Principle
A quadratic complex equation has a squared unknown. For real coefficients, complex numbers make every quadratic solvable, even when the discriminant is negative.
The complex number system contains square roots of negative real numbers because \(i^2=-1\).
Notation
- \(z\) is the unknown complex number.
- \(a\), \(b\), and \(c\) are real coefficients.
- \(\Delta=b^2-4ac\) is the discriminant.
- \(i\) is the imaginary unit, with \(i^2=-1\).
Method
Start with:
Multiply by \(4a\):
Move the constant term:
Add \(b^2\) to both sides:
Factor the left-hand side:
Then solve for \(z\). If \(\Delta\lt0\), write \(\Delta=-|\Delta|\), so \(\sqrt{\Delta}=i\sqrt{|\Delta|}\).
Rules
For real coefficients, non-real roots occur in conjugate pairs. If \(u+iv\) is a root, then \(u-iv\) is also a root.
Examples
Solve:
Here \(a=1\), \(b=2\), and \(c=2\). The discriminant is:
Because \(\Delta\lt0\), use the negative-discriminant form:
Simplify:
Checks
- Confirm that the equation is actually quadratic by checking \(a\ne0\).
- Use \(i\sqrt{-\Delta}\), not \(\sqrt{\Delta}\), when \(\Delta\lt0\).
- For real coefficients, check that non-real roots are conjugates.
- Substitute one root back into the original equation when signs are uncertain.